problems getting last element in a directory string

nails October 5, 2012 at 06:20:56

The basename command is what you are need. This is one of many links on this forum that describes the basename command and a shell scripting solutions: http://www.computing.net/answers/un... Let me know if you have any further questions. nails

I tried a few of these and stll no luck. What I am doing is reading through a file line by line in a do loop. Each line has the full location of each directory that needs to be backed up. In the backup directory, I need to only use the last element on the filename to create a backup directory. So I have a file called filelist.txt and it will have 1-n lines in it. I read this file and need to process each one to get for example /usr/programs/scripts/project. For this I just need to get projects into a separate variable to use.

nails October 8, 2012 at 07:17:42

#!/bin/ksh while read myline do myvar=$(basename $myline) echo $myvar done < filelist.txt

requirements have changed (don't they always). I am reading in a bunch of file directories from a file called filelist.txt. I don't have any issues with this. Each of the filenames can be variable length strings. I now need to break up each level into separate variables such that \\onedir\\twodir\\threedir\\fourdir need to be in separate variables so the value of var1 = onedir var2 = twodir var3 = threedir var4 = fourdir

nails October 8, 2012 at 15:56:03

Use eval to create dynamic variables: #!/bin/ksh counter=0 while read myline do ((counter+=1)) eval var${counter}=$(basename $myline) done < filelist.txt echo $var1 echo $var2 echo $var3 echo $var4 # dynamically list out the $var variables num=1 while [ "$num" -lt $counter ] do eval echo \"\$var${num}\" ((num+=1)) done