Solved can you please explain what does the command will do

ijack August 17, 2012 at 04:58:13

✔ Best Answer

By itself, nothing. If you define the variables it will search the directory $ftp_ldir for filenames containing the string $ftp_file.

Hi, Thank you and can you please explian the below also.If i wont give the third part that is (if [ "$ftp_DBvar1" -eq "fci" ]; then)it is creating one file in local directory by condition 1.but if i give the 3rd condition it is creating an other file with the file name "ftp_file" which we are ftping, along with the file "ftp_lfile" in local directory .this ftp_file is having list of all files of remote server path from where we are ftping the file. Is there anything wrong in the code ? echo [`date`] Starting FTP from "$ftp_host" server >> "$script_output_file" echo "$ftp_file" | grep "*" if [ $? -ne 0 ] then ftp_getcmd="get" else ftp_getcmd="mget" fi ftp -i -n -v <<-ftpend1 open "$ftp_host" user "$ftp_user" "$ftp_pass" "$ftp_mode" lcd "$ftp_ldir" cd "$ftp_rdir" "$ftp_getcmd" "$ftp_file" "$ftp_lfile" quit ftpend1 if [ "$ftp_rarc_required" = "Yes" ]; then ftp -i -n -v <<-ftpend2 open "$ftp_host" user "$ftp_user" "$ftp_pass" "$ftp_mode" lcd "$ftp_ldir" cd "$ftp_rdir" #ls -l $ftp_file #if [ $? -eq 0 ] #then #mv "$ftp_file" "$ftp_rfile" mdelete "$ftp_file" cd "$ftp_rarc_dir" mput "$ftp_file" quit ftpend2 fi if [ "$ftp_DBvar1" -eq "fci" ]; then ftp -i -n -v <<-ftpend3 open "$ftp_host" user "$ftp_user" "$ftp_pass" "$ftp_mode" cd "$ftp_rdir" ls -l "$ftp_file" if [ $? -eq 0 ] then #if [ "$ftp_file" ]; then zip "ftp_rfile" $ftp_file rm -f $ftp_file fi quit ftpend3 fi echo "FTP Operation Complete " >> "$script_output_file"