Here is my script, when it i used I get a missing operand. message, can someone explain why it doesn't work? @ECHO OFF

:SETTING

SET /A D=1

SET /A P=1

:SETTING2

SET /A D=%D%

SET /A P=%P%

:LOOP

ECHO Type a number for the calculator to process for phi.

SET /P N=

SETLOCAL EnableDelayedExpansion

FOR /L %%A IN (1,1,%N%) DO ( SET /A X=!D! +!P!

SET /A D=%P%

SET /A P=%X%

)

ECHO %X%

PAUSEI have tried to replace the !s with %s and it still gives me the same error.

You don't need to call for an arithmatic operation (SET /A) when just defining or re-defining a variable. Just use SET with no parameters. I removed the "/A" where not needed, worked for me.

@Echo off :SETTING SET D=1 SET P=1 :SETTING2 SET D=%D% SET P=%P% :LOOP ECHO Type a number for the calculator to process for phi. SET /P N=">> " SETLOCAL EnableDelayedExpansion FOR /L %%A IN (1,1,%N%) DO ( SET /A X=%D%+%P% SET D=%P% SET P=%X% ) ECHO %X% PAUSEIf infinity is infinite, is the square root of infinity infinite as well?

- Kurp Von Steiner

Thank you, but no matter what I put in it gives me 2, when the answer for a self calculated equation for this would be 377. I think it has something to do with this part: SET D=%P%

SET P=%X%Yet I am unsure about that.

message edited by Glacier

First get rid of this:

:SETTING2

SET D=%D%

SET P=%P%Not because it interferes with the logic, but simply on principle. It does nothing but clutter up the code.

The only other thing I had to change was % to ! in the two SETs, from this:

SET /A D=%P%

SET /A P=%X%

to this:

SET D=!P!

SET P=!X!

(I took out the /A because it's not necessary for assigning values, only for doing math)

You don't need the /A in these two steps, (but, SET /A eliminates the need for either % or !, so that's an alternative, in these two lines:

SET /A D=P

SET /A P=X

would also work. (Welcome to batch scripting!)

and you don't need the exclams in the prior SET /A, but that doesn't matter. This worked on my end.

message edited by nbrane

Thank you, yet, as I have stated before, the answer that I should get when I input 12 is 377, but no matter what I enter I get 2 as the answer. Here is my script so far: @ECHO OFF

:SETTING

SET D=1

SET P=1

:LOOP

ECHO Type a number for the calculator to process for phi.

SET /P N=

SETLOCAL EnableDelayedExpansion

FOR /L %%A IN (1,1,%N%) DO (

SET /A X=%D%+%P%

SET D=!P!

SET P=!X!

)

ECHO %X%

PAUSEI have already fixed this by using an IF command, but I am doing this to learn how to use FOR commands.

-EDIT-

I tried replacing the %N% in the IN statement, what I found is that it still only gives me 2, so I am thinking that it has something to do with with this:

SET /A X=%D%+%P%-EDIT 2-

I figured it out, what the problem was is I needed to replace the %D% and the %P% with !D! and !P!, this gives me the needed answer, 377 when input is 12.

message edited by Glacier

Thanks to everyone that has helped me here.

Yeh, "spot on":

SET /A X=%D%+%P%should be:

SET /A X=D+PRule of thumb, for batch: "set slash A, vars away" (I know, that sucks.) Simply, don't use variable-notation in SET /A statements. SET /A does not do algebra, so it knows that any letter-items are to be expressed as variable-values, without the usual % or !

The only exception is "system" variables, like %%a, %%z, etc. These must have notations, and then be very cautious around modulo! (expressed as %%).

message edited by nbrane

Ask Your Question

Weekly Poll

Do you think Microsoft can save the Surface Book lineup?

Discuss in The Lounge

Poll History