stored name in array

Razor2.3 August 20, 2010 at 10:11:13

i mean, how to write the codes? With a text editor. I doubt anyone will do your homework for you, but I've been proven wrong before.

shutat August 21, 2010 at 11:17:52

hmm... int arr[10] = { 0 }; // 0-9 elements arr[0] = some_val; ... arr[9] = some_val; scanf("%d", &arr[desired_index]); // dangerous approach or cin >> arr[desired_index]; // dangerous approach Strings a bit different depending on if they're c-style strings or cpp's string class. char str[2][80] = { "", "" }; strcpy(str[0], "some string"); fgets(str[0], sizeof str[0], stdin); // side effect of leaving '\n' but safe cin >> str[0]; // side effect breaks on white space cin.getline(str[0], sizeof str[0], '\n'); or string s[2] = { "", "" }; s[0] = "some string"; cin >> s[0]; // side effect breaks on white space getline(cin, s[0], '\n'); HTH ------------------------------------------- I have no aspiration for preaching. ;-)

Mark system enter mark for: jose : 99 max : 87 ian : 77 grade report name no mark grade jose 02 99 A max 01 87 A ian 09 77 B- analysis: Average mark : ... highest mark : ..... lowest mark : ..... A: ...% A-: ...% B: ....% .... above is the output. Q: the coding? or any idea to write the code? ** i know i must use array, but i don't know how to store the mark input by user into the name listed.. smbdy help me..

shutat August 28, 2010 at 00:13:08

I'd use structured data myself. typedef struct { char name[80]; int grades[MAX_GRADES]; char lettergrade; } students; students records[MAX_STUDENTS]; If you need to use the static arrays, declare 2D arrays int grades[MAX_STUDENTS][MAX_GRADES]; char names[MAX_STUDENTS][80]; char letter[MAX_STUDENTS]; storing would be for(int i = 0; i < MAX_STUDENTS; i++) { cin.getline(names[i], sizeof names[i]); for(int j=0; j < MAX_GRADES; j++) { cin >> grades[i][j]; } } where i is the index of the current student and j is the index of the current grade for student[i] You need a dimension for the total number of students in order to keep the records in order. HTH ------------------------------------------- I have no aspiration for preaching. ;-)

btw. i have to use C language. i not yet learn C++. huhu tq :)

shutat August 28, 2010 at 06:48:16

replace cin with fgets and you're all set. for converting the numbers, try sscanf char nbuf[10]; ... // code fragment from above for(j = 0; j < MAX_GRADES; j++) { do { // output grade message fgets(nbuf, sizeof nbuf, stdin); } while((sscanf(nbuf, "%d", &grades[i][j])) != 1); } The names are similar... fgets(names[i], sizeof names[i], stdin); gravy no?? HTH ------------------------------------------- I have no aspiration for preaching. ;-)

probs here. need some help! if(mark[i] >= 85) { grade[0]='A'; count++; } else if(mark[i] >= 80) grade[i]='A'; else if(mark[i] >= 75) grade[i]='A-'; else if(mark[i] >= 70) grade[i]='B+'; else if(mark[i] >= 65) grade[i]='B'; else if(mark[i] >= 60) grade[i]='B-'; else if(mark[i] >= 55) grade[i]='C+'; else if(mark[i] >= 50) grade[i]='C'; else if(mark[i] >= 0 && mark[i] < 50) grade[i]='E'; } printf("%d.%s\t\t%d\t%d\t%c\n", i+1, name[i], matric[i], mark[i], grade[i]); i try to print out the character A-. but it only print - sign what should i do with it? 1 more; i don't know how to calculate the % of grades? any suggestions/formula?

shutat August 31, 2010 at 19:28:50

grade[index] = 'A-' will not work because you are trying to store two characters when there is space for one. if you want to do that, declare char grade[MAX_STUDENTS][3], and then use strcpy(grade[i], "A-"); or whatever is appropriate. do you mean each student's grade average? if so, (mark[STUDENT_INDEX][0] + mark[STUDENT_INDEX][1] + mark[STUDENT_INDEX][n_number_of_marks - 1]) / n_number_of_marks. If not, then you'll need to clarify a bit. HTH ------------------------------------------- I have no aspiration for preaching. ;-)