|If this is the level of question asked nowadays on computer science courses then it explains a lot.|
I copied the question exactly as it was written
Is this from a text book, or some kind of question sheet your instructor made up themself? I suspect the latter. If the former, I'd request the school change to a different text book.
Here's what I see when I look at the original question you posted:
DEFAULT GATEWAY 172.16.1.1
First, the IP and netmask combined give you the following network using CIDR notation:
Here are your available host IP's in that subnet:
First IP: 172.16.2.1
Last IP: 172.16.3.254
Broadcast Address: 172.16.3.255
There is no mention of a router, much less what networks any interfaces on said (missing) router may be on. Ergo the following: DNS 192.168.1.1 is useless and completely meaningless because you can not get to 192.168.1.1 from 172.16.2.0/23 without a router that contains minimum two interfaces with one on each subnet and static routes in between.
Therefore, clients on the 172.16.2.0/23 network CAN NOT communicate with the internet as they have no viable DNS address............period, end of story.
Also, if you take a look at 172.16.2.0/23 you'll see that DEFAULT GATEWAY 172.16.1.1 is not within the subnet so again, it's not a reachable IP address without some kind of a router involved between 172.16.2.0/23 and 172.16.1.1 so clients on 172.16.2.0/23 cannot reach that particular gateway IP and therefore cannot leave their own immediate subnet.
So, essentially, what you have is a closed LAN that has no external access of any kind. Therefore the question cannot be answered using any of the 4 supplied (incorrect) responses.
It matters not how straight the gate,
How charged with punishments the scroll,
I am the master of my fate;
I am the captain of my soul.