Solved Class A using Class C mask, how many subnets and hosts?

February 14, 2012 at 16:34:31
Specs: Windows XP
I'm new to this I just started the course but somehow I'm really confused about this assignment. Hopefully someone can help me out thanks.
The question is

1. The entire class ā€œAā€ address 10.0.0.0 uses a class ā€œCā€ subnet mask. How many valid subnets are available and how many hosts are supported?

From my understanding I wrote 256 subnets and 254 hosts. Hopefully this is the answer.
if I did get this right then the second question is the thing I don't get. And the question is

2. In the previous example host 10.0.2.1 is located on which subnet #? (eg: first subnet, 2nd subnet, 100th subnet?)

Can someone give me a hand? Thanks



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✔ Best Answer
February 15, 2012 at 08:31:36
et1984 think about it this way

you have this huge pie [class a]. with 255.255.255.0 and 10.0.0.0 you have 254 ips right?

where is the rest of the pie?
so if you had 10.0.1.0 with 255.255.255.0 you have another 254 ips
if you set 10.0.2.0 with same subnet you have another 254
if you set 10.0.3.0... see where this is going?

Now do you understand where the 65536 is coming from?

Answers are only as good as the information you provide.
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#1
February 14, 2012 at 17:42:02
Check your math with online subnet calculators.

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#2
February 14, 2012 at 18:31:04
I did try using one but it says
Host address range 10.0.0.1 - 10.0.0.254
Hosts per Subnet 254
Maximum Subnets 65536

Where does the 65536 especially after it says host address range is from 10.0.0.1 - 10.0.0.254

It doesn't show how things are calculated so I'm somehow confused.


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#3
February 14, 2012 at 23:24:18
You need to reread your textbook explaining IP addresses, classes, and subnetting. Better still, ask your tutor to explain it to you.

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#4
February 15, 2012 at 08:31:36
✔ Best Answer
et1984 think about it this way

you have this huge pie [class a]. with 255.255.255.0 and 10.0.0.0 you have 254 ips right?

where is the rest of the pie?
so if you had 10.0.1.0 with 255.255.255.0 you have another 254 ips
if you set 10.0.2.0 with same subnet you have another 254
if you set 10.0.3.0... see where this is going?

Now do you understand where the 65536 is coming from?

Answers are only as good as the information you provide.
How to properly post a question:
Sorry no tech support via PM's


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#5
February 15, 2012 at 13:25:44
ah! thanks "wanderer"

so it'll be like 10.0.0.0 for the first subnet id and the first ip can be assigned will be 10.0.0.1 and after the ip went up to 10.0.0.254 (.255) broadcast then it'll be 10.0.1.0 for the 2nd subnet id and 10.0.2.0 for the 3rd subnet id.


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