I need to read first n lines from a .txt file using ms dos batch file. The file looks like: abc efge 123 ... Anybody knows how to write the batch file? Thanks.

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Replace N with the number of lines to be accessed. By the way this NT batch NOT DOS. @echo off & setlocal EnableDelayedExpansion set max=N set cnt=0 for /F "delims=" %%j in (text.txt) do ( set /A cnt+=1 if !cnt! grt %max% goto :DONE echo.%%j ) :RONE

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Thanks IVO. Actually I tried the similar script with ms-dos batch file. But it doesn't work because cnt value is not updated until out of the for loop. Thát's, when executing "if %cnt% grt %max% goto :DONE", cnt is always "0" :(

To list first n lines of a text file, use the following script. # Script listn.txt var str file var int n # Read file into a variable. var str content ; cat $file > $content # List first $n lines to screen. lex (makestr(int($n))+"]") $content Script is in biterscripting. Save the script as C:/Scripts/listn.txt. Run the script as script "C:/Scripts/listn.txt" file("C:/somefolder/somefile.txt") n(2) Above will list the first 2 lines of file C:/somefolder/somefile.txt. Always include files and paths in double quotes. Similarly, the following command will give you the number of lines present in the file. len $content The documentation for these commands is at http://www.biterscripting.com/helpp... . Sen