(It's **** near impossible to search for this since "%" is ignored in almost all search engines... ) I'm trying to use the very common "Print directory listing" context menu batch file in Vista. However, %1 is not returning the directory I am selecting. I tested this by just trying to echo or cd %1 and I just get blank output - if I put quotes around "%1", I only get quotes (for echo). %0 still works and shows the batch file name, but no parameters after that (1,2,3,4...) have any output (just says "echo is on"). Help? Weird huh? I have already added the shell command key for directories in the registry (Printdir.bat) Here's the test batch: echo %1 dir %1 /-p /o:gn >"%temp%\Listing.txt" start /w notepad "%temp%\Listing.txt" del "%temp%\Listing.txt" exit BTW, sfc, AVG, and Mbam didn't find any problems. I'm running Vista Ult.SP1. edited by moderator: language

What does your HKEY_CLASSES_ROOT\Directory\shell\Print Directory Listing\command\(default) registry entry look like?

default value is "Printdir.bat" (I have the batch file in c:\windows ).

Try changing it to: "%systemroot%\printdir.bat" "%1"

Ahah! That didn't quite work... gave me an error about not having permission to access the specified folder - even on in my own user directory. But I did find what works... "Printdir.bat" "%1" Thank you for your time and effort and hopefully this will help someone else out.