I need my Windows server to access the network by static Ip address how to set that on TCP/IP prorties I have 192.165.110.2 255.255.255.0 192.165.110.1 but when I click ok it automatically jump back to DHCP why??

Windows Server gets this problem, when the Server name includes capital letters. Use a server name in lower case letters, then give the server the static ip. Should work. Paul

Paul, thank you for the reply, but not yet the error message is"Multiple default gateways are intended to provide redundancy to a single network ( such as an intranet or the Internet) they will not function properly when the gateways are on two separate, disjoint networks ( such as one on your intranet and one on the Internet ) do you want to save this configuration?" we have a router to hind the real Ip address, right now the situation is if we use the router we can connect to network, other wise we can't connect to network. why!!

Am I right? The problem to bind a static ip to the Server is solved? Assuming that your server has a static ip now. You don' talk about how many network cards are in that server. I guess there is only one network card in it. So if you get the error message, that there are multiple gateways configured, there is another problem and this problem is in the registry. So lets figure out, what happens right now. Right click the "My Netiwork Places" and choose properties. You should get a list of your LAN-Connections. So if the entry is named LAN-Connection 2 or 3 and so on, thats the problem. In this case, windows hasn't changed the old entry in the registry but has created a new one e.g. named "LAN-Connection 2". And now Windows gets confused and takes a bit of both entries in the registry to configure the actual network connection. The only thing you can do is, to remove both entries from the registry. After that, the easiest way is to restart windows server and configure the new found LAN-Conntetion. It's hard to desxribe, how to remove the correct registry entries here. So if you need further information about that, let me know. Paul

Hi Paul, Thank you for the reply. It seems the problem get solved. for some stupid reason. our school cancel our network registration. I am a coding personer, not much ideal on network, if you can explain more that would be so nice. 1)I have two network card, it did have LAN -connection and LAN-connection2 in there. why we need two network card. I mean what advice I didn't use yet? 2)how to build a remote connection to that server, if some PC is DHCP can we set up something, only allow one or two PC to remove connect to that Win server? best regard!

1.) If you have 2 network cards, the entries LAN-Connection and LAN-Conneciion2 are absolutely ok. But sometimes Windows shows 2 LAN-Connections by only one physical network card and that is is big problem. 2 network cards are used to connect one of them to e.g. the internet and the other to the local network. So you can install a firewall to manage the traffic from the internet to the local network and only the needed traffic will be passed through the local net. It's also a good idea to have a seperate network card for the internet, if someone tries to hack into your server. If there are no other options to get the hacker out of your system, you simply can deactivate the network card for the internet and figure out where the security hole is. But, if the server is still runnig, the local users can continuesly use the server. 2.) There are several options to connect to the server remotely. You can connect via VPN (Virtual Private Network) and will get only access to the drive mappings. Another option is to use Terminal-Services. If you need more than 2 remote connections at a time, you'll need additional Terminal Client Licenses, that must be bought. Both remote access solutions can be managed in the ADS. You can allow or deny remote access for each user. I hope, this will aswer your questions. Paul

Paul, Thank you for the reply on questions one. on question two maybe I confuse you, I really mean VPN Remote desktop may I have more information on that?