Hello All,

The script need to read a file, which contains such as follows:

Mary age22 address1
Peter age33 address2
eof

then all data put into variable

Output like : name = Mary
age = age22
address = address1

name = Peter
age = age33
address = address2

awk '$2 = substr($2,4) { printf "name = %s\nage = %s\naddress = %s\n\n", $1, $2, $3 }' infile

If you want output formatting, David gave you a solution for that.  If you need to load the fields into variables so that you can work with the variables, the script below provides an example:

while read name age addr other
do
# echo name=$name age=$age addr=$addr
printf "name=%-10s age=%-6s addr=%s\n" $name $age $addr
done < infile

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Thanks.

I have another question.

If I want to get exactly field size of name, age and address. What should I do?

for example: input name = char 5
age = char 2
addr = char 40

while true
$read name | cut -d -f,5
$read age | cut -d -f,2
$read addr | cut -d -f ,40
do
# echo name=$name age=$age addr=$addr
printf "name=%-10s age=%-6s addr=%s\n" $name $age $addr
done < infile

Can I do like that?

Thanks and Regards,
Apple

If you are asking how to pull variables from each line of your file based upon fixed column positions, then I believe you have the general idea of it. In the ksh script below, the while-loop reads each line of infile into the $line variable, then I show two different ways to split up $line based upon fixed column positions.

IFS=""

while read line
do

name=$(expr "$line" : "\(.....\)")
age=$(expr  "$line" : ".....\(..\)")
addr=$(expr "$line" : ".......\(.*\)")

#name=$(echo $line | cut -c1-5)
#age=$(echo $line | cut -c6-7)
#addr=$(echo $line | cut -c8-)

printf "name=%-6s age=%-3s addr=%s\n" $name $age $addr
done < infile

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