I'm getting a little frustrated and would appreciate any help. I'm writting a unix script, and no matter what I do, it ignores the command line variables. At this point, I'm just trying to echo out what the value is to prove that it is coming in. The script is: # check input parameters echo $0 echo $1 echo $2 echo $3 echo $# echo $* I run it by typing it: ./run_it 1 2 3 and the output is: ./run_it 0 Any ideas? Thanks

Could it be you need the #!/bin/some_shell line at the top?

Well, I'm a noob, but I added in the line indicating what shell i'm using #!/bin/ksh it didn't work at first. I then started typing fast and furious, trying different combinations of, basically: /bin/ksh ./run_it 1 2 and it didn't work at first..but then suddenly it did work. The only problem is, I didn't pay attention to what I was typing and closed the window. So I've another newbie question: If you were to invoke this script in the korn shell, how would you do it?

Just as you have done! 1) write the script, putting magic string in the first line 2) $> chmod +x script_file 3) $> ./script_file arg1 arg2 ... argn I can't see what could be wrong. The only other thing I can think of is that some OSes don't recognise #!/bin/ksh - they need a space: #! /bin/ksh. You could look for some scripts in the systemwide /bins that take arguments and see if they are working properly.

Just had another thought - try print instead of echo.

Thanks for the help. Neither made any different. I think something quarky is going on. I'm going to skip this issue and move on. Thanks again.