Hi, Can anyone tell me why I get the different exit status for the following script execution: Script A ---------- ksh -c "/proj/prog.exe " 2>>/tmp/run.log 1>/tmp/error.log << ! ^M ! ret_code=$? Script B -------- ksh -c "/proj/prog.exe " << ! ^M ! ret_code=$? Why am I getting different exit status (ret_code) from script A and script B? The correct return code should be from the program - prog.exe which is 100, but I am getting exit status as 1 in script A ? Why? I am suppose to use method script A but how to get the correct return code in this case?

Not having your executable, I can only guess, but have you tried surrounding the whole command in double quotes: ksh -c "/proj/proj.exe 2>> /tmp/run.log 1> /tmp/error.log << ! ^M !" Maybe the ksh -c being spawned doesn't know what to do with stdout and stderr. Two other observations: 1) ^M is an actual carriagle return? 2) Based on the file names, don't you really mean this:? 2>>/tmp/error.log 1>/tmp/run.log

Yes, ^M is an actual carriagle return. I have tried the following, but still having the exit code as 1 instead of 100: To put the whole command in double quote: ksh -c "/proj/proj.exe 2>>/tmp/error.log 2>/tmp/error.log" << ! ^M ! Any other clue to solve this?