if the file is as; -rwxrwx--- 1 vadwb gadwb 75 25 abr 13:42 CONTADOR.ENT.D070120 i need only the file name and the time"13:42 " please help

Are you asking for a shell script? Your OS says Win XP

shell script

I don't recognize the format of your ls command, but in the string provided, you are asking for the eighth and the last fields. This awk script prints the 8th field, a space, and the last field: line="-rwxrwx--- 1 vadwb gadwb 75 25 abr 13:42 CONTADOR.ENT.D070120" echo "$line"|awk ' { print $8" "$NF } ' Just substitute your ls command for the echo "$line"

if the file has spaces, the awk code will break. # ls -tlr | awk '{for(i=1;i<=7;i++) $i=""}1' or # ls -tlr | awk '{for(i=8;i<=NF;i++){printf "%s ",$i};print ""}' GNU win32 packages | Gawk