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unix awk printf
Name: nnn22 Date: May 23, 2004 at 18:22:24 Pacific OS: winXP CPU/Ram: celeron 1GHz/256
Comment:
Hi how to filter this variable(or data)below into only numbers multiple of 0.02(i.e. 0.00, 0.02, 0.04, ...1.00) using awk (may be with printf) command?:
Name: Wolfbone Date: May 23, 2004 at 19:53:12 Pacific
Reply:
awk '{if ((100*$1 % 2) == 0) print}'
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Response Number 2
Name: nnn22 Date: May 25, 2004 at 16:01:15 Pacific
Reply:
thank you Wolfbone for your help
but I have strange result with some values in if statement condition(100*$1 % 2)like : (0.14) should be(0) I get (1.77636e-15) (0.28) should be(0) I get (3.55271e-15) (0.56) should be(0) I get (7.10543e-15) (0.58) should be(0) I get (2) which stop these values to show in the output, I tryed Bourne shell and Bash shell gives the same result its very strange, is it a bug in awk or something wrong happen somewhere? it works fine if you use (bc) but not awk, try it your self !!!!!
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Response Number 3
Name: Wolfbone Date: June 1, 2004 at 06:28:30 Pacific
Reply:
Heh! - yes it's not very impressive. Awk just treats everything as a float and uses the crude machine arithmetic to do it's work. I should have realised that would happen and it's not really a bug in awk. I see you already found a workaround but you could also test for the remainder of the last digit on division by 2.
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