Can someone help with the script i'm trying to write; it uses sed. I think i'm doing something wrong with syntax. The script is supposed to replace str1 with str2 in any number of files....... I'm having trouble with sed recongnizing the 2 string arguments

version of unix is SunOS 5.8
HERE IS CODE::::::

UW PICO(tm) 4.0 File: replace Modified

#!/bin/csh

set find = $1
set replace = $2
@ count = 0
@ x = $#argv - 2

while($count < $x)

sed 's/$find/$replace/g' $3
shift
@ count++
end

***************
ANY help is greatly appreciated
thanks

Hi,

Adding brackets may help.

sed 's/${find}/${replace}/g' $3

sed won't perform variable substitution using single quotes. try this:

sed "s/$find/$replace/g" $3

-jim