Hi, I am facing a serious problem.Please tell me what is my mistake? My script goes like : #!/bin/ksh for file in send*.log do if[ -f ${file}] then grep "filename inside the file" ${file} >> temp grep "process number" ${file} >> temp assigning variable: set pnum=cat temp|tail-1 temp #temp has both filename & process number echo " $pnum " #has to display pnum from temp main script: set -v ndmcli EOJ select statistics pnumber=${pnum};#here above pnum value is not assigned. why this problem does it requires any conversion from file output to assign EOJ else exit fi done I need to execute the above statement very badly: select statistics pnumber=${pnum}; if give value user input ,it assigns. but as a file output,it doesn't assign help me tell me what wrong i did thank u nanda_anu

There's a good thought. If no one answers your homework question immediately, post it 10 or 15 more times under different names. Hope that works out for you. BTW you don't need to check for the existence of a file you just got from the for command.

Even after removing if statement also my variable is not assigned inside the script Try to give solution: in order to assign the value of a variable in the following select statistics pnumber=<pnum>; my pnum value should be ex:16244 from an another file

You set a variable in ksh with var=value not set var=value To evaluate a command and retrieve its value, use var=$(command...) tail returns the last n lines of a file. "cat filename | tail" does the same thing but less efficiently and with more typing.

Please post a sample of your data file. We will be able to provide you with a better answer. for file in `find . -type f -name "send*.log" -exec grep -l pattern {} \; ` ; do pnum=`process number' $file done