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Shell Script Help

Comment:

Can someone tell me what the following line of code does. ls $SOURCE/$DATE* 2>&1 > /tmp/ediin$$ I have a hard time to understand it especially the "2>&1 > /tmp/ediin$$" part. Thanks.

Name: David Perry
Date: April 11, 2005 at 11:39:37 Pacific

Reply:

2>&1 redirect stderr to stdout $$ is the process ID of the script It should be written as ls filename* > /tmp/outfile$$ 2>&1

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Name: Luke Chi
Date: April 17, 2005 at 15:54:51 Pacific

Reply:

More info: In Unix: There are 3 standard file handlers 0: standard input 1: standard output 2: standard error output Luke Chi

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