sed help

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Original Message

Name: Orasparkle
Date: March 25, 2005 at 20:08:10 Pacific
Subject: sed help
OS: XP
CPU/Ram: P4 & 512

Comment:

I have a file with 5k records & each record is of the following format "first name last name DOB". I am having problem removing the DOB(Date ) column which is in the following format (MM/DD/YYYY).
Orasparkle

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Response Number 1

Name: eng_sammer
Date: March 25, 2005 at 20:27:55 Pacific
Subject: sed help

Reply: (edit)

I need your help ... please how can I download the following driver :
S3 396/397 display card

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Response Number 2

Name: wollie
Date: March 26, 2005 at 06:34:48 Pacific
Subject: sed help

Reply: (edit)

Orasparkle,
if you want to eliminate the last column just make use of awk to cut it off
greet$
Wollie

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Response Number 3

Name: nails
Date: March 26, 2005 at 16:58:15 Pacific
Subject: sed help

Reply: (edit)

Wollie is right; use awk to print the fields you want:
awk ' { printf("%s %s\n", $1, $2) } ' myfiles
If you insist on using sed, this works, but I still don't recommend it:
sed 's/ *$[^ ]* *$$//' myfile
Nails

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awk/sed help Sed Help [/] sed help sed help with variable length file Sed help????	dumb sed question Sed Help. sed help Sed help SED - Del Last Char of every record

ymessenger error (freebsd...

sed comand

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