Hi all, This is a simple script for some other I’m doing, but before change example1 I wanted to test with an example 2. The code must be work this way. ./test James Good morning James--- END ./test nojames Usage: ./test James or james. Code I have done, but Im having a hard brain fart, is this. #!/bin/bash name=$1 if ($name != “James” -o $name != “james” ); then echo "usage: $0 James or james" exit 1 else echo "Good morning $name" fi Don´t freak out until you know the facts...Relax...!

Try [] instead of (). Try -a instead of -o.

I already did that before, but didnt help, some other clue ? Thanks. Don´t freak out until you know the facts...Relax...!

Also make sure that: there is a space/blank right after [ there is a space/blank right before ] What happens?

Great, it worked. But, what does -a do ?... why didnt it work with -o, I had made some other codes with -o and it work ?.. Thanks Guy... Don´t freak out until you know the facts...Relax...!

Are you familiar with boolean algebra? In shell the -a is the "and" and the -o is "or". ($name != “James” -o $name != “james” The above reads if name is NOT James or name is NOT james, it is true. If you stop to think about it, with an "or" either [Jj]ames is still true. Check out this link: http://en.wikipedia.org/wiki/Boolea... click on "AND" for further info. If you stil have trouble, try something like this: # untested if [ $name = "James" -o $name = "james" ] then : else echo "name is not [Jj]ames" fi

thanks Nails. I already got some torrents for O'Reilly bash scripting. and found some interesting links, including yours, but it will always be helpfull to post here ;) Don´t freak out until you know the facts...Relax...!