I am using the following awk script: BEGIN { OFMT = "%10.4f"; } END { print "Test Starting" > "testfile"; l1 = 675.5 l2 = 306.9 l3 = 613.8 l4 = 135.1 l5 = 82.5 l6 = 135.1 l7 = 400 l8 = 82.5 t = 17.5; t1 = l1 * t / 100; t2 = l2 * t / 100; t3 = l3 * t / 100; t4 = l4 * t / 100; t5 = l5 * t / 100; t6 = l6 * t / 100; t7 = l7 * t / 100; t8 = l8 * t / 100; print "t1 = " t1 >> "testfile"; print "t2 = " t2 >> "testfile"; print "t3 = " t3 >> "testfile"; print "t4 = " t4 >> "testfile"; print "t5 = " t5 >> "testfile"; print "t6 = " t6 >> "testfile"; print "t7 = " t7 >> "testfile"; print "t8 = " t8 >> "testfile"; total = 0; total = total + l1 + t1; print "total 1 = " total >> "testfile"; total = total + l2 + t2; print "total 2 = " total >> "testfile"; total = total + l3 + t3; print "total 3 = " total >> "testfile"; total = total + l4 + t4; print "total 4 = " total >> "testfile"; total = total + l5 + t5; print "total 5 = " total >> "testfile"; total = total + l6 + t6; print "total 6 = " total >> "testfile"; total = total + l7 + t7; print "total 7 = " total >> "testfile"; total = total + l8 + t8; print "total 8 = " total >> "testfile"; } The output will be: Test Starting t1 = 118.2125 t2 = 53.7075 t3 = 107.4150 t4 = 23.6425 t5 = 14.4375 t6 = 23.6425 t7 = 70 t8 = 14.4375 total 1 = 793.7125 total 2 = 1154.3200 total 3 = 1875.5350 total 4 = 2034.2775 total 5 = 2131.2150 total 6 = 2289.9575 total 7 = 2759.9575 total 8 = 2856.8950 2856.89 But, I need 2856.90 (two decimal ROUND off). Is there any other way to do this? Thanks in advance Sudhakar

You can use bc. Here is an example: #!/bin/ksh print "scale=2; 33/1000" | /usr/bin/bc This will return .03 So, if A=10 B=3 print "scale=2; $A/$B" | /usr/bin/bc This will return 3.33

Here i am getting 3.33 If I'm using the A=20, it is giving 6.66 . But, I need 6.67 And, I need to do this calculation in awk script itself. Let me know if you have any ideas on that. Thanks. Sudhakar

Sudhakar, Try this - $>echo | awk '{s = 8 / 3; printf "%5.5f\n", s}' 2.66667 $>echo | awk '{s = 8 / 3; printf "%5.3f\n", s}' 2.667 $>echo | awk '{s = 8 / 3; printf "%5.1f\n", s}' 2.7 $>echo | awk '{s = 8 / 3; printf "%5.0f\n", s}' 3 HTH. Boudhayan.

Thanks Buodhayan. But, in my case i am getting result as 2856.8950. If you use %5.2f, it is giving the following result: $> echo | awk '{s =2856.8950; printf "%5.2f\n", s}' 2856.89 But, I am expecting 2856.90 Let me know if you have any ideas on this. Thanks. Sudhakar