Hi,
does anyone know how to write a script (prob using pgrep/pkill) to kill processes
that making more than 5 copies of ITSELF ??
Thanks
PS: this is quite urgent, please help. I got
one reply yesterday, but i'm still in doubt.
Please gimme a hand. My manager gonna ask for it soon. Thanks

To answer your first question, yes.
The following works with solaris

#!/bin/ksh
if [ $# -gt 0 ]; then
process_name=$1
ps_count=`ps -ef | grep -v 'grep' | grep -v 'kill' | grep -i -c $process_name`
echo "Process count: $ps_count"
if [ $ps_count -le 5 ] ; then
exit 0
fi
set -A array_name `ps -ef | grep -i $process_name | grep -v 'grep' | grep -v 'kill' | awk '{print $2}' | sort -u`
print "ps -ef | grep -i $process_name | grep -v 'grep' | grep -v 'kill' | awk '{print \$2 \$8}' | sort -u -n"

print "${array_name[*]}"
kill_count=0
while [ $kill_count -lt $ps_count ]
do
kill -9 ${array_name[$kill_count]}
((kill_count=kill_count+1))
done

else
print "Usage: $0 process_name"
print ""
fi

Thanks a lot..however, what if i don't know
the name of the process, then can I do a
pgrep -ef first to take note which process
is having more than 5 copies of itself, then
execute the procedure above, then do a pgrep
-ef again to check (this should be done
inside a loop) until no more processes are
having more than 5 copies ?
however, i know that every one is busy,
struggling with their own bosses P:), so
this is a *HUGE* help for me, thanks a lot
David. If you got some spare time, then any
further discuss, hint about this topic is
more than welcome.
Cheers