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Problem: Extract YR&QTR in c shell

Original Message
Name: stakuri
Date: January 10, 2008 at 08:44:22 Pacific
Subject: Problem: Extract YR&QTR in c shell
OS: unix
CPU/Ram: AIX
Model/Manufacturer: AIX
Comment:
Hi,I'm using c shell and trying to create a variable which will determine the YEAR and QTR based on the `date`. For ex:2007Q4. I'm pasting my code below. The logic is right but the script doesn't work. Its giving the following error: "Badly placed ()'s."

Can someone please help me resolving this..Here is my code:
Thanks in adv!
ST

#!/usr/bin/csh

setenv YEAR `date +%Y`
setenv MONTH `date '+%m'`

if (( $MONTH >= 1 && $MONTH <= 3 )) then
setenv QTR 4
elif (( $MONTH >= 4 && $MONTH <= 6 )) then
setenv QTR 1
elif (( $MONTH >= 7 && $MONTH <= 9 )) then
setenv QTR 2
elif (( $MONTH >= 10 && $MONTH <= 12 )) then
setenv QTR 3
endif

if (( $QTR >= 4 )) then
setenv YR echo `expr ${YEAR} - 1`
else
setenv YR echo `expr ${YEAR}`
endif

echo ${YR}Q${QTR}
exit


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Response Number 1
Name: nails
Date: January 10, 2008 at 19:57:45 Pacific
Subject: Problem: Extract YR&QTR in c shell
Reply: (edit)
First, your if syntax is incorrect, and, second, lose the echo when setting YR:

#!/usr/bin/csh

setenv YEAR `date +%Y`
setenv MONTH `date '+%m'`

if ( $MONTH >= 1 && $MONTH <= 3 ) then
setenv QTR 4
else if ( $MONTH >= 4 && $MONTH <= 6 ) then
setenv QTR 1
else if ( $MONTH >= 7 && $MONTH <= 9 ) then
setenv QTR 2
else if ( $MONTH >= 10 && $MONTH <= 12 ) then
setenv QTR 3
endif

# elimiate the echo:
if ( $QTR >= 4 ) then
setenv YR `expr ${YEAR} - 1`
else
setenv YR `expr ${YEAR}`
endif

echo ${YR}${QTR}
exit


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Response Number 2
Name: stakuri
Date: January 17, 2008 at 11:30:15 Pacific
Subject: Problem: Extract YR&QTR in c shell
Reply: (edit)
THANK YOU!!!....I got confused with c shell and k shell syntax..

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