hi All, have a script which searches log files looking for some text. can someone tell me how to print the file name only if the text is in that particular file ?? currently my script prints out all the file names it goes through : #!/bin/ksh find ./ -name "SystemOut*.log"|while read LINE; do grep "$1 : OES \[LOGIN\]" $LINE; echo "$LINE"; done thanks in advance, Cesar.

Why don't you use the grep -l option?

because it doesnt work :)

You can use echo $? after and if its success print the values . Vasanth

hi Vasanth, sorry didnt understand your reply. did you mean to say check if the grep command was successful then print the line ? i.e if [ "$?" -ne "0" ]; then echo $LINE; fi if so, this wont work as the grep command will be successful, it just wont find any results and print out the file name which is what i am trying to avoid. thanks.

ooops meant to say : if [ "$?" -eq "0" ]; then

I just tried simple command in my box to check the return status and its perfectly worked $ cat a.txt I am able to grep $ grep am a.txt I am able to grep $ echo $? 0 $ grep ap a.txt $ echo $? 1 In ur case it will successful means it always return some values ? Vasanth