Dear All, I'm using following script to calculate Yesterday's Date as a portion of a huge script. #!/bin/ksh set -A DAYS Sat Sun Mon Tue Wed Thu Fri Sat set -A MONTHS Dec Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec YESTERDAY=$((`date +%d` -1)) MONTH=`date +%m` YEAR=`date +%y` NDAY=`date +%u` WEEKDAY=${DAYS[`date +%u`]} if [ $YESTERDAY -eq "0" ] then MONTH=$((MONTH-1)) if [ $MONTH -eq "0" ] then MONTH=12 YEAR=$((YEAR-1)) fi set `cal $MONTH $YEAR` shift $(($# - 1)) YESTERDAY=$1 fi TMONTH=${MONTHS[MONTH]} $YEAR echo $YESTERDAY$MONTH$YEAR Date format that I need is yymmdd (030203). When d or m lessthan 10 required date format doesn't maintain. e.g. if the date is 030203 it displays Yesterday's date as 03022 (which should be 030202). Appreciate your help to resolve this Prb.

Hi Nish, use typeset -Z2 YESTERDAY=$((`date +%d` -1)) This will help. No RISK no fun Frank

I think to do this properly you have to convert to a julian date format, do the arithmetic, and convert back. I had to write something similar recently and I started out trying to do it the easy way and it just got difficult. It's a bit long to post here but it's at http://www.williamrobertson.pwp.blueyonder.co.uk/code/shift_date.txt (or www.williamrobertson.net, Korn shell, shift_date). btw, why declare #!/bin/ksh then use sh syntax with if [ $MONTH -eq "0" ] when you can do it in ksh with if [[ $MONTH = 0 ]] or even (if MONTH is an integer though I don't see it declared as one) if (( MONTH == 0 )) Also the usual convention is uppercase for exported variables, lowercase for others.

Dear Frank/William, Thanks a Lot for your help ! Cheers, Nish.