Dear All,
I'm using following script to calculate Yesterday's Date as a portion of a huge script.

#!/bin/ksh
set -A DAYS Sat Sun Mon Tue Wed Thu Fri Sat
set -A MONTHS Dec Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
YESTERDAY=$((`date +%d` -1))
MONTH=`date +%m`
YEAR=`date +%y`
NDAY=`date +%u`
WEEKDAY=${DAYS[`date +%u`]}
if [ $YESTERDAY -eq "0" ]
then
MONTH=$((MONTH-1))
if [ $MONTH -eq "0" ]
then
MONTH=12
YEAR=$((YEAR-1))
fi

set `cal $MONTH $YEAR`
shift $(($# - 1))
YESTERDAY=$1
fi
TMONTH=${MONTHS[MONTH]}
$YEAR
echo $YESTERDAY$MONTH$YEAR

Date format that I need is yymmdd (030203). When d or m lessthan 10 required date format doesn't maintain.
e.g. if the date is 030203 it displays Yesterday's date as 03022 (which should be 030202).
Appreciate your help to resolve this Prb.

Hi Nish,

use
typeset -Z2 YESTERDAY=$((`date +%d` -1))

This will help.

No RISK no fun
Frank

I think to do this properly you have to convert to a julian date format, do the arithmetic, and convert back. I had to write something similar recently and I started out trying to do it the easy way and it just got difficult. It's a bit long to post here but it's at http://www.williamrobertson.pwp.blueyonder.co.uk/code/shift_date.txt (or www.williamrobertson.net, Korn shell, shift_date).

btw, why declare #!/bin/ksh then use sh syntax with
if [ $MONTH -eq "0" ]

when you can do it in ksh with
if [[ $MONTH = 0 ]]
or even (if MONTH is an integer though I don't see it declared as one)
if (( MONTH == 0 ))

Also the usual convention is uppercase for exported variables, lowercase for others.

Dear Frank/William,
Thanks a Lot for your help !
Cheers,
Nish.