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pattern matching/replacing with sed

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Name: MVal
Date: January 11, 2005 at 13:41:09 Pacific
OS: HPUX
CPU/Ram: HP
Comment:

Hi,

I am trying to do the following simple operation with sed, but it wouldnt work because sed doesn't allow me to use variables in the replace string. Anyway to do it ?

testvar="TestFilename.#.txt"
testdate=`date +%m%d%Y`

resultvar=`echo $testvar | sed -e s/#/$testdate`

Here $testdate in the expression fails.

Basically I want to replace the "#" with today's date.

Your help is appreciated ...

regards
-MVal



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Response Number 1
Name: vgersh99
Date: January 11, 2005 at 13:53:38 Pacific
Reply:

resultvar=`echo $testvar | sed -e "s/#/$testdate/"`


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Response Number 2
Name: nails
Date: January 11, 2005 at 13:55:17 Pacific
Reply:

You forgot the terminate /:

resultvar=`echo $testvar | sed -e s/#/$testdate/`


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Response Number 3
Name: MVal
Date: January 11, 2005 at 14:02:28 Pacific
Reply:

Thanks vgersh99, putting the replace statement in double quote solves the problem..

Thank nails, yes I forgot the ending '/' also...



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