I need a KornShell script that will, among all the users currently logged on to the system, find a slot of one hour that contains the most number of users. I know how to list all the users currently logged on but how do I do anything with the times that are listed? Please help, thanks.

Have your script run in a loop and run the following -- date and 'w'. Exit your script after you are done collecting your metrics. Write another little script to parse the output and create a pretty chart. Mark

Here is a short script that may help. It is very simplistic and you can concatenate the echo output to a log file if you wish. #!/bin/ksh eval `date '+hour=%H minute=%M second=%S'` end_hr=`expr ${hour} + 1` end_time="${end_hr}:${minute}:${second}" until [ -z ${now_time} -eq ${end_time} ] do now_time=`date +%H:%M:%S` numr=`who | wc -l` echo "${numr} users are logged on at ${now_time}" sleep 60 done