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loop through directory grep file at
Name: Eric_1 Date: May 9, 2005 at 03:20:15 Pacific OS: AIX CPU/Ram: N/A
Comment:
Hello all,
I have a directory containing a files. I need a function which loops through the directory and greps 2 attributes out of the files.
The file looks like:
Name='Eric' FMASK='^Eric_1'
The function should return Eric and Eric_1
process Eric and Eric_1 and grep the next name out of the next file in the directory.
Name: Eric_1 Date: May 9, 2005 at 07:26:09 Pacific
Reply:
This is what I have till now.
for i in `ls -a *.txt` do FILENAME=$i name=$(cat $FILENAME | grep Name) Name=${Name#name=} done
This loops through the directory, finds all the text files and gives back the Name. However, it gives it back with the quotes like: 'Eric' and I just need the Eric and the Eric_1
Thanks in advance
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Response Number 2
Name: David Perry Date: May 10, 2005 at 04:40:12 Pacific
Reply:
#!/bin/sh set -xv for file in `find . -name "*.txt" -exec grep -l Name {} \; ` ; do name=`awk -F= '/Name/ { print $2 }' $file | sed -e "s/'//g"` fmask=`awk -F= '/FMASK/ { print $2 }' $file | sed -e "s/'//g"` echo "Name: $name Fmask: $fmask" done
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