I am tryng to learn shell scripting, and i am still in the begining stages of learning. I have a book that teaches unix, and it says that the correct structure for an "if...then" statement is if elif else fi, but when i write my script i always get a syntax error on "fi", "elif", and "else" i will include my sample script, please tell me what am i doing wrong! if [ $# = 0 ] then echo Error! Paramater requred. exit 1 fi if [ "$1" = "Dog" ] then echo Bow Wow! elif [ "$1" = "Cat" ] then echo Meow! else echo Error!: Invalid Paramater fi

I haven't done any scripting before and I need to write the following script. The name of the script will be lab6 It will be invoked with a parameter of at least two digits. Example: lab6 105 The date will be displayed on the screen. The script will extract the last digit of the input parameter. This will be compared to the last digit of the current day of the month (E.g. Christmas is on day 25; use the 5). A message will then be displayed on the screen indicating if the digits are the same or not. The script will request the user to enter a number between 1 and 10. The script will display the number and its square on the screen

Answer to the first post: You are missing semi-colons between the test and "then": if [ $# = 0 ]; then echo Error! Paramater requred. exit 1 fi if [ "$1" = "Dog" ]; then echo Bow Wow! elif [ "$1" = "Cat" ]; then echo Meow! else echo Error!: Invalid Paramater fi -jim

Also, enclose your echo commands in double quotes, so the shell doesn't get them: if [ $# = 0 ]; then echo "Error! Paramater requred." exit 1 fi if [ "$1" = "Dog" ]; then echo "Bow Wow!" elif [ "$1" = "Cat" ]; then echo "Meow!" else echo "Error!: Invalid Paramater" fi -jim

Jim, thank you so much, i can't believe i overlooked that! I feel really silly now that i realize what it was, and I appreciate your help very much. Thanks Again, Freedom