how to write a shellscript which can do that.
That display on the screen
-how many user logged in
-newlogins since last sample
-who has logged out since las sample
-how many processe started since last sample.
When killed
-report long it the script run
-report how many time the script have run
- how many login and logout in the priod
- remove all temporay files used

Please post what you have done so far and questions about the trouble spots. Don't expect someone else to do your homework.

man who
man last
man rm
man acct

Dear David

could tell me how the write the command to display the who log out. please thank

write the output of who to a file

who > /tmp/who.out

When the script is run again, move the last sample so it is not overwritten

if [ -f /tmp/who.out ] ; then
mv /tmp/who.out /tmp/who.tmp
who > /tmp/who.out
diff who.tmp who.out | awk '// { print $1 }'
else
echo "No previous who sample.
fi

hi David
here i do a shell script that is to display the how many log in and out. But when i run is they display error message. could fix it for me and i want to display only number of people that log in and out. i don't wan't the whole listed. thank you very very much for your Help.

$cat watchwho
#whatwho: watch who log in and out

new=/tmp/wwho1.$$
old=/tmp/wwho2.$$
>$old

while:
do
who >$new
diff $old $new
mv $new $old
sleep 60
done| awk '/>/ {$1 = "in: ":print}
/>/ {$1 = "out: ":print}'