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how to match pattern on Bash?
Name: nelsmy Date: November 23, 2005 at 00:39:53 Pacific OS: windows xp CPU/Ram: pentium 4
Comment:
Below is a perl script, if i want to get the string preceed the match pattern, i can use variable $`, but how do i do it in bash? can anyone show me?
$_ = "this is a sample string"; /sa.*le/; # matches "sample" within the string # $` is now "this is a " # $& is now "sample" # $' is now " string"
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