Hi Experts, Using unix-KSH script, we need to calculate the difference between two time intervals. for example; time_a=04:35:54 time_b=00:00:05 (pls. note that this shows only seconds) Now, the required script should subtract the time_b from time_a and show the output. Your help would be highly appreciable. Thanks. Regards, Rajinikanth

60 seconds in a minute and 3600 seconds in an hour. Use the set command to parse the time string into 3 arguments: #!/bin/ksh time_a=04:35:54 set - $(IFS=":"; echo $time_a) tta=$(( ((3600 * $1) + (60 * $2)) + $3)) echo $tta time_b=00:00:05 set - $(IFS=":"; echo $time_b) ttb=$(( ((3600 * $1) + (60 * $2)) + $3)) echo $ttb # difference in seconds tdiff=$(($tta - $ttb)) echo $tdiff

using awk [code] awk ' BEGIN { an = split ( "04:35:54", atime, ":" ); bn = split ( "00:00:05" , btime ,":" ); totala = ( atime[1] * 3600 ) + (atime[2] * 60 ) + atime[3] totalb = ( btime[1] * 3600 ) + (btime[2] * 60 ) + btime[3] total = totala + totalb print "total time taken: " total " secs." }' [/code]