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i need help! can someone help me please?
i try to calculate date under unix (ksh)...example:
todays date: 2003.07.23
date-5
= 2003.07.28how can i do calculate?
i know that it is not possible with
the date command!thanks a lot
jonny schulz
Jonny
You can use the following, changing to the appropriate time zone. Check out the man page for date:
TZ=GMT-80 date +%Y.%m.%d
If putting in a script run within ` ` (not'')
Phil.
0 
Wow! Never knew you could do that!
That allows a date arithmetic script like:
#!/bin/ksh
integer days=$1
format=$2if (( days < 1 ))
then
sign="+"
(( days *= -1 ))
else
sign="-"
fiTZ=${TZ}${sign}$(( 24 * days ))
date ${format}
0
thanks many for your help but unfortunately doesn't run.
I get the answer "GMT-80 not found".Be aimed my is:
we have todays date: 2003.07.24 (date +'%Y.%m.%d')
now I start a script: test1.sh 30 (30 = $1)
I want to get back: 2003.06.28 (with echo $xxx)how can I realize this?
0
Jonny:
Dealing with dates in unx is pain. We've dealt with this before. Look at:
http://www.computing.net/unix/wwwboard/forum/5223.html
Regards,
Nails
0
What is test1.sh?
If you have a script "add_days" exactly like the one I posted above (using Phil's awesome Timezone modifier), then
add_days -30
should give (today being 24th July):
Tue Jun 24 16:42:02 GB 2003
You can add your format mask:
add_days -30 +'%Y.%m.%d'
2003.06.24
This works on Solaris, maybe it won't on Dynix.
Alternatively follow Nails' link - I wrote the "shift_date" script before I heard of the TZ trick.
0
Hmm, TZ doesn't seem to exist on FreeBSD (just tried). Maybe you can only modify the timezone at runtime this way on particular versions of Unix.
0
oh oh oh
its very hard to work with dates under unix, because there is no spezify tool for it!
my solution is, that "we" have a oracle server installed on the unix machine, so i can calculate the date with sql:
backup_datum=`sqlplus -s EOF
user/password
set head off
set feed off
select to_char(sysdate - $1 ,'YYYYMMDD') from dual;
EOF`this is another way to do it!
william: test1.sh is means only
name of the script: test1
writing in: sh (shell) :-)regards
Jonny
0
Jonny,
You posted an update to the earlier thread #5223, including your "calculate_date.sh" script, but this forum won't let me post to it because it's too old, so I'll try to continue here.Well that's one heck of a script.
I haven't worked out what it all does yet, but it did happen to notice the leap year calculation is wrong (it just tests whether $year % 4 is zero - not the same thing!)
However, the original question was:
> how do I get today's date minus 'x' into a variable of the form 'YYYYMMDD'?
Well, today's date in the format YYYYMMDD is
date +'%Y%m%d', e.g. 20030809.and to get that date minus 10 (say) using my shift_date script (see link above), just enter:
shift_date $(date +'%Y%m%d') -10which gives (today being 20030809)
20030730If you want that in a variable for naming files, just use
archive_date=$(shift_date $(date +'%Y%m%d') -10)
Is that what you need, or am I missing something?
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