Hi people,,, Does anyone know any hexadecimal editor for Unix (native and non-native) ??? I have a file that contains as last character a number, but when i visualize it with a hex editor i see a "dot" ( a0 ) as the last character ... Anyone know how can i erase this "dot" in a command line ?? for example ... i have a file called test. # cat test 123456 the last character is 6 ... but when i use a hex editor, it shows the following 31 32 33 34 35 36 a0 this correspond: 123456. this s u c k s a lot ... there are a program that process this file and this program show a message error always that get files that contains this "dot" and i need process this file,, and the unique way is erase this dot that i cant see using vi editor. thanks people

That a0 is not a . They entering this command: #!/bin/ksh print '\n' | od -hc Your output will look like this: 0000000 0a0a \n \n What you are seeing is a new-line character. It is a line terminator.