Hi Guru's, I would like to grep a particular string in a file and the output should print the line containing the grep'd string and next line also. Can this be done using native grep or thru some script ? Thanks for your help in advance Cheers ex: --- start of file foo ---- abcd efgh ijkl mnop qrst uvwx --- end of file foo ---- if i grep for efgh in foo grep -i efgh foo ( should return ) efgh ijkl Thanks.

if you have Python on your HPUX (i suppose) you can do this: f = open(your_file) while 1: line = f.readline() if line == '': break if "efgh" in line: print line print f.readline() f.close() Note that awk, sed , perl...even the shell can be used to do what you want. But i am not familiar with them..so just wait for replys from other gurus...:)

If you have access to GNU grep (i.e. Linux. see gnu.org to download it for your *nix version), it contains an after context, -A, and before context, -B, options. So with GNU grep you could do: # untested grep -A 1 -i ... Of course, you can always write a script like ghostdog. This link has a context script: http://www.unixreview.com/documents/s=9455/ur0412b/ur0412b.html