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Grep Command Help
Name: Chinmaya Date: August 16, 2005 at 03:10:33 Pacific OS: HP-UX CPU/Ram: NIL
Comment:
Hi All,
In a file I want to grep a string. I want to get a result not only greping line but also the 4 lines below it.
Example:
File A contains following lines
ABC 123 11/07/05 MONDAY FROM LEICESTER UK XYZ 123 01/07/05 FRIDAY FROM BANGALORE INDIA ABC 222 16/08/05 TUESDAY FROM LONDON UK
After I grep string ‘ABC’ the result file should contain following lines
ABC 123 11/07/05 MONDAY FROM LEICESTER UK ABC 222 16/08/05 TUESDAY FROM LONDON UK
Name: Luke Chi Date: August 16, 2005 at 05:16:37 Pacific
Reply:
#!/usr/bin/sh
CT=0 cat 5 | while read LINE do if [ "$CT" -gt 0 ]; then echo $LINE CT=`expr $CT - 1` continue fi echo $LINE | grep $1 > /dev/null 2>&1 if [ $? -eq 0 ]; then echo $LINE CT=3 fi done
Luke Chi
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Response Number 2
Name: Luke Chi Date: August 16, 2005 at 05:20:11 Pacific
Reply:
Forgot one thing:
You need to pass the search string, for example:
$ program.sh ABC
Luke Chi
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Response Number 3
Name: Luke Chi Date: August 16, 2005 at 05:40:32 Pacific
Reply:
Forgot another thing:
cat 5 <===== 5 is your input filename
Luke Chi
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Response Number 4
Name: aka Date: August 18, 2005 at 13:59:44 Pacific
Reply:
Do this
grep -A9 ABC (file)
Don´t freak out until you know the facts...Relax...!
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Response Number 5
Name: aka Date: August 18, 2005 at 14:01:44 Pacific
Reply:
Adding
-A9 means 9 files AFTER ABC
Try, and let me know
Don´t freak out until you know the facts...Relax...!
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Response Number 6
Name: Chinmaya Date: August 21, 2005 at 07:55:23 Pacific
Reply:
Thanks a lot Luke and aka for your scripts and commands. I could get my intended result by script.
aka, the command grep -A9 ABC (file) is not working.
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