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gamble with varible content

Comment:

Hi all, My problem is say y=z x=y now i want to assign the content of y to a varibal called var. var=$y is one way. but i dont want this method. i want assign the contne of y to var using variable x only like var=${$x} this is my assumption and this what exactly i want. i hope u understand my problem. reply as soon as possible.. thanks in advance....

Name: nails
Date: November 21, 2005 at 23:45:03 Pacific

Reply:

One way .... #!/bin/ksh y=z x=y eval var=\$x echo $var # should echo 'y'

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Name: Jim Boothe
Date: November 22, 2005 at 09:27:13 Pacific

Reply:

I think what arun.s wants is to assign to var the contents of a variable whose name is held in the variable x. So you do need the double evaluation: y=z x=y eval var=\$$x echo $var # will echo contents of $y

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Reply:

Hi, thanks guys especially thanks for jim for providing the solution..

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Reply:

Hehe. Bash ariphmetic is dificult for use in shell. Ibaul, wbr

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