Hi, I'm getting an error message: "Specify a parameter with this command" when I'm executing the following code - ------ Header_Info=`head -1 ${LoadDir}/${FileName} | awk '{print $1}'` RowCount=`wc -l ${LoadDir}/${FileName} | awk '{print $1}'` RowCount=`expr $RowCount - 2` Number_of_Records=`echo $Header_Info | cut -c 111-117` echo "$FileName,$RowCount,," >> $FinalDir/$Header_File if [ $RowCount -eq $Number_of_Records ] ---------- The error message is pointed at the line with 'if' condition. As far as I can see, I've specified the proper parameters. Can anyone please suggest why this error is occuring and how to correct it. Thanks, Anil

I believe that the Number_of_Records variable that you are cutting out of Header_Info is null. Do an echo right before that if-statement to prove it: echo "Number_of_Records=$Number_of_Records" if [ $RowCount -eq $Number_of_Records ] ... If that is a valid situation, one way to avoid the syntax error is to use double_quotes: if [ $RowCount -eq "$Number_of_Records" ] ...