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echo wildcard in variable
Name: abhargav Date: May 14, 2005 at 02:25:52 Pacific OS: unix CPU/Ram: 256 SDRAM
Comment:
hi i m iterating /etc/shadow file now i want to pick the second field which is a wild card "*" or encrypted password i m using a simple for loop
#/bin/sh
for WHO in `awk -F":" '{print $2}' /etc/shadow` ; do echo "$WHO" echo ${WHO} done i m just wants to print if it is a "*" then it should be * but it prints out the files in that directory becoz by default echo "*" will list files.is there any way i can print "*" root:$1$Kij0PSF0$b8zSNlahpjmC1wlqA6seZ1:12868:0::::: bin:*:9797:0::::: daemon:*:9797:0::::: adm:*:9797:0::::: lp:*:9797:0::::: sync:*:9797:0::::: shutdown:*:9797:0::::: halt:*:9797:0::::: mail:*:9797:0::::: news:*:9797:0::::: uucp:*:9797:0::::: operator:*:9797:0:::::
hi my question is abt scripting. i want to find the diffrence in two dates. dates are in /var/log/messages
Mar 27 05:48:02 abhargav sshd[1151]: Apr 2 15:31:17 abhargav sshd[1151]:
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Summary: hi all i m just stuffed in a problem if somebody can help me out i hav /etc/shadow file with enteries like bin:*:9797:0::::: daemon:*:9797:0::::: adm:*:9797:0::::: lp:*:9797:0::::: sync:*:9797:0:::::...
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