How to delete a character that is before the last character in all the lines in sed? plz...........do this favour for me

sun

I couldn't figure out a regular expression to do this. However, using bash variable expansion, you can do a 2 step process: save the last char, and then remove the last two charcters and glue the saved character back on:

#!/bin/bash
while read var1
do
   lc=${var1:((${#var1}-1))} # save the last char
   var1=${var1%%??}${lc} # trim the last two chars and glue back the last char
   echo "$var1"
done < datafile

sed 's/.\(.\)$/\1/' file

ThanQQQQQQQQQQQ

sun

Hey, Dog!

Good one!

Nails