I want to convert date passed as a variable in the format 'DD-MON-YY' i.e., '31-JUL-08' to 'YYYYMMDD' format '20080731' . Someone gimme a single line command. Anybody here, help...! TIA TIA Covina

If someone can post from the otherway, it's fine with me, i.e., convert from 'YYYYMMDD' to 'DD-MON-YY'. TIA Covina

You'll never do this in one line because of having to convert the year string to a number: #!/bin/ksh # This korn shell function receives a date of the format # 01-AUG-08 and returns a string YYYYMMDD function yrmmdd { typeset -2Z mm typeset -2Z yr # parse the argument into $1, $2, $3 set - $(IFS="-"; echo $1) yr=$3 dd=$1 case $2 in "JAN") mm=1;; "FEB") mm=2;; "MAR") mm=3;; "APR") mm=4;; "MAY") mm=5;; "JUN") mm=6;; "JUL") mm=7;; "AUG") mm=8;; "SEP") mm=9;; "OCT") mm=10;; "NOV") mm=11;; "DEC") mm=12;; *) echo "error" exit ;; esac echo "20"${yr}${mm}${dd} } # end function dstr=01-AUG-08 retstr=$(yrmmdd $dstr) echo $retstr In fact, I answered a similar question for you here: http://www.computing.net/answers/un...

Using ksh93, I can be done as a one-liner. $ printf "%(%Y%m%d)T\n" "31-JUL-2008" 20080731