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comparing dates from a file
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Original Message
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Name: Ashoke Bhowmick
Date: September 27, 2002 at 04:08:19 Pacific
Subject: comparing dates from a file
OS: Unix
CPU/Ram: 5.2
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Comment: Hi , I am new to Unix environment.I have a generated file containing the contents of a directory. The file (dir.txt) is something like following. 08-19-02 04:42PM 443463691 jul02.zip
08-20-02 02:22PM 443463691 jul02new.zip Please guide me in writing a shell script that will read the file(dir.txt) and identify which file (jul02.zip etc) is the latest one and do some processing accordingly. Thanks in advance and regards,
Ashoke Bhowmick
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Response Number 1
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Name: David Perry
Date: September 27, 2002 at 04:55:54 Pacific
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Reply: (edit)ls has a parameter to sort by date. Try
ls -last dir/* otherwise you can use awk and cut to pull fields for comparison
year=`head -1 dir.txt | cut -f 3 -d '-' | awk '{print $1}'`
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Response Number 2
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Name: Ashoke Bhowmick
Date: September 27, 2002 at 05:05:48 Pacific
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Reply: (edit)Hi ,
Thanks for quick reply. I won't be able to use the "ls -last dir/*" command, since the file is generated by doing an FTP to a remote server and listing the files using ls command. The FTP protocol doesn't have powerful set of commands.I am not sure whether there is an equivalent command for FTP to sort files according to date. I don't have a telnet access to that remote server. I would try out the second option suggested by you.
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