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awk to print last parameter

Comment:

Hi could anyone help me print out the last parameter of a line usd=ing awk and a field delimiter? For example... Input : Dir/dir/dir/file awk -F / {print last parameter} I can't use print $4 since I don't know how many subdirs there are. Thanks. Regards, Jean-Philippe Beaudoin

Reply:

No need to reply. Just got the solution myself. nawk -F / '{print $NF}' :-) Jean-Philippe Beaudoin

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Reply:

awk provides NF for the number of fields. So it will give you the integer for the number of fields on a line. Use as below: awk -F/ '{print $NF}' <filename> Hope it helps, Rajesh

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find'em: search.sh

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