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Awk in a script

Comment:

When running the script below I get nothing.. I am a newbie with this. Not sure If you can run awk in a script. Also Im having problems getting a variable from the command line to the script. from command line; ./getnode IQSB script #!/bin/ksh db=$0 awk ' /Database name =/ { db_found = ($4 == "$db" ? 1 : 0); } /Node name =/ && db_found { print $4 } ' listdb.txt

Reply:

The first parameter is $1 and not $0 ($0 is the script name). The substitution $db is not done in the awk script : solution 1) db_found = ($4 == "'$db'" ? 1 : 0); solution 2) Use awk variable: awk -v DB="$db" ' . . . db_found = ($4 == DB ? 1 : 0); #!/bin/ksh db=$1 awk -v DB="$db" ' /Database name =/ {    db_found = ($4 == DB); } /Node name =/ && db_found {    print $4 } ' listdb.txt Jean-Pierre.

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