Security & Virus | Hardware | Windows XP | Windows Vista | PC Gaming

Arrays in Shell scripting

Comment:

H, When I am using set -A command for creating an array, an error is thrown "bad option(s)" when the value is negative. eg. set -A array_name -1 3 5 can any one provide a solution.... thanks.

Name: nails
Date: October 15, 2009 at 23:16:17 Pacific

Reply:

The only way I can see to do it, is to declare your array elements using this method: #!/bin/ksh typeset array_name[0]=-1 typeset array_name[1]=3 typeset array_name[2]=5 echo ${array_name[0]}

0

Count files by date in a ...

compare rows

Summary: Dear all, I wonder how to find the size of an array in shell script. For example, I declared an array as following: #! /bin/sh a = (1 adf 8 2 se) How could I get the size of the array a? I had searche...

Summary: Can someone please provide sample code that utilizes arrays. Or please direct me to a web site that provides good explanations onhow to implement arrays in shell scripts. Thanks, J. ...

Summary: Hi, I'm trying to run loops in shell scripts using the following script. loop=1 while [ loop -lt 10 ] do echo 'this is my $loop text-line' loop='expr $loop + 1' done ---- but I'm getting error: test: ...