I have a question about inputting strings.
char* tester;
tester = malloc( sizeof(char) * 100);

scanf("%s", tester);
printf("\nThe String: %s\n", tester);
exit(1);

If, for example, I input "test string", the string returns "test" and does not record anything after the whitespace. So I have 2 questions:
1) How do I record the string without using array notation.
2) Is there a way to dynamically allocate memory to the string so that I can input a string of any size?

Thanks,
Igor

Hi
My C's a bit rusty.
scanf() function will quit on a blank spaces.
This will get your string correctly.
scanf("%s %s",tester) but gets(tester) would be much better with strings.

Why not RTFM? As pointed out, you are getting what you asked for with scanf: the first word alone.

info libc 'I/O on streams' 'Formatted Input'

info libc 'I/O on streams' 'Line Input'

see getline()

Hey,
wanna scan a whole line including blanks and tabs? Use the following

scanf("%[^\n]", tester);

For dynamically allocating space for a string use linked lists. I think you are familiar with data structures, right?

Best of luck.

Santanu Sen
National Institute of Technology
Durgapur
India

How big is the line? How big is tester?... You could make that work properly using the GNU 'a' flag for dynamic string input to scanf but getline is the right way to get a whole line of input anyway, not scanf.

Linked list? What's wrong with realloc - I don't think Igor is writing a Lisp implementation ;-)

It was suggested earlier to use gets() instead of scanf(). In my opinion, gets() is the most useless crap in C, because it lets the user type more than 100 character and cause a segfault in your program. Instead, use fgets(), and have it read from stdin.