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re: converting char array into int
Name: mydreams84 Date: September 26, 2004 at 08:02:38 Pacific OS: unix CPU/Ram: don't know
Comment:
Hi there,
I am a Java programmer transitioning into a C++ programmer and I'm still new at all of this. Even for Java I'm still new at it. My problem is that if I read in a character array of numbers as well as letters, how can i pick out ONLY the numbers from the character array and then convert them into integers? In java, there's functions to determine whether the string is a letter or a number.. but how about c++??
Name: BlueRaja Date: September 26, 2004 at 20:16:16 Pacific
Reply:
int chartoint(char c) { if((c>='0')&&(c<='9')) return(c-'0'); else return 0; }
AKhalifman@hotmail.com
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Response Number 2
Name: Savage2k5 Date: September 26, 2004 at 20:26:07 Pacific
Reply:
You can compare the the read character to other characters out there. '0' is equal to 48 in ascii, and '9' is equal to 57 in ascii. So any chars casted to ints that fall between 48 -> 57 is a number. Then all you have to do is subtract 48 from the ascii value to get the real number value.
char temp = array[i]; int result; if ((int)temp > 47 && (int)temp < 58) result = (int)temp - 48; //offset of ascii
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