Is it possible to pass an entire array by a functions argument without having to list the entire set .... ie (x[1],x[2],x[3]...)??? If so, is it even more so possible to pass by reference? Thanx, justin PS: I'm using Dev 4 C++ and know this is capable under other languages, dont in in True Basic, but c++ is a tad bit different

I use visual C++ myself and usually use the CArray template object for setting up arrays. However your question relates more to C and passing simple arrays to functions. The functions void foo( int X[] ); void foo( int *X ); are equivalent. Both pass the address of array X to the function. The console program main(int argc; char* argv[]) { int x[10]; foo(x); printf("foo is %d, %d, %d", x[0], x[1], x[2]); getchar(); return 0; } foo( int X[]) { X[0] = 1; X[1] = 3; X[2] = 5; } will print "foo is 1,3,5" Please note that array the index always starts at 0; You must keep track of the length of the array which is passed. Either it is known or you pass a length argument to the function; If you try to write data past the end of the array you will create a difficult to find bug. Thats why I should examine your template library for an array class.

Thankyou much that answers question ;]