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Parse first/last character in batch

Comment:

Can anyone help come up with a solution. I'm trying to simply parse the quotes from strings read in from a file. Each string starts and ends with a quote ("). I just want to drop the first and last character. I do not want to drop any quote nested inside the string. Thanks!

Name: Mechanix2Go
Date: April 6, 2009 at 06:30:39 Pacific

Reply:

:: drop first and last char @echo off > newfile & setLocal EnableDelayedExpansion for /f "tokens=* delims=" %%a in (myfile) do ( set str=%%a set str=!str:~1,199! set str=!str:~0,-1! echo !str!>> newfile ) ===================================== If at first you don't succeed, you're about average. M2

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Name: ghostdog
Date: April 6, 2009 at 17:52:56 Pacific

Reply:

if you can download tools like sed for windows (check my sig), then this is all you need c:\> sed -i.bak "s/\"//g" file Unix Win32 tools | Gawk for Windows

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