Hi, I am writing a batch file. I am accepting the parameter from user and trying to display message depending on the parameter entered. Here is the batch file content @ECHO OFF SET /P USERPARM=Enter the Value : IF "%USERPARM%"=="" ECHO Nothing is entered ELSE IF "%USERPARM"=="Y" ECHO Success ELSE IF "USERPARM"=="N" ECHO Failure. ENDIF But when user enters value instead of displying message command prompt is getting closed. Please let me know if this code has any errors. I am new to batch programming. Thanks Arun S

@ECHO OFF :LOOP SET /P USERPARM=Enter the Value : IF "%USERPARM%"=="" ( ECHO Nothing is entered GoTo :LOOP ) IF /I "%USERPARM%"=="Y" ( ECHO Success ) ELSE ( IF /I "%USERPARM%"=="N" ( ECHO Failure ) ELSE ( ECHO The param entered is not Y/y nor N/n ) ) :: End_Of_Batch Notes: - Avoid nested IF as they become unreadable. - Use IF /I to avoid upper/lowercase difference. - ENDIF is not a batch statement.