I need soem help regaridng one script i want to write. I am a new bie in writing scripts, so this doubt may be a simple one. I am trying to apply a parsing program to a set of input files in a directoy. How can i access all the files from a source directory , one by one and to write the output files with another name to some directory ? i.e my exe file is a.out I have input files 1.txt,2.txt .. in one directory. I need this cmd line ./a.out <inputfilename> > <outputfilename> , on all input files. can i write a loop to get all files like this ? right now i am writing the same line again and again to apply to all files.. Plz give your suggestions. Thank u Shinni

I think you should try the linux forum. M2

I'm a Perl guy and only know the barest minumum of Bash, so this syntax might be a little off. #!/bin/bash for file in *txt do     $num++     ./a.out $file > $num.out done